Reputation: 1149
I'm trying do a optimization with cia_ensure_values without repeat the same condition for each cia_ensure
My tables:
|policies|
|id| |client| |policy_business_unit_id| |cia_ensure_id| |state|
1 MATT 1 1 0
2 STEVE 1 1 0
3 BILL 1 2 0
4 LARRY 1 2 1
5 MATT 1 2 1
6 STEVE 2 2 2
7 BILL 2 2 2
8 LARRY 2 2 1
9 MATT 2 1 1
|policy_business_units|
|id| |name| |comercial_area_id|
1 LIFE 1
2 ROB 1
3 CAR 1
|comercial_areas|
|id| |name|
1 MICROSOFT
2 APPLE
|cia_ensures|
|id| |name|
1 ORANGE
2 BT
3 ATT
4 MOVISTAR
5 SPRINT
Here is the information:
http://sqlfiddle.com/#!2/89491/1
I'm trying to create a query when it has values will repeat in my query
SELECT pb.name as unit,
SUM(CASE WHEN p.state =0 AND ce.id=1 THEN 1 ELSE 0 END ) AS v1,
SUM(CASE WHEN p.state =1 AND ce.id=1 THEN 1 ELSE 0 END ) AS a1,
SUM(CASE WHEN p.state =2 AND ce.id=1 THEN 1 ELSE 0 END ) AS n1,
SUM(CASE WHEN p.state =0 AND ce.id=2 THEN 1 ELSE 0 END ) AS v2,
SUM(CASE WHEN p.state =1 AND ce.id=2 THEN 1 ELSE 0 END ) AS a2,
SUM(CASE WHEN p.state =2 AND ce.id=2 THEN 1 ELSE 0 END ) AS n2,
SUM(CASE WHEN p.state =0 AND ce.id=3 THEN 1 ELSE 0 END ) AS v3,
SUM(CASE WHEN p.state =1 AND ce.id=3 THEN 1 ELSE 0 END ) AS a3,
SUM(CASE WHEN p.state =2 AND ce.id=3 THEN 1 ELSE 0 END ) AS n3,
SUM(CASE WHEN p.state =0 AND ce.id=4 THEN 1 ELSE 0 END ) AS v4,
SUM(CASE WHEN p.state =1 AND ce.id=4 THEN 1 ELSE 0 END ) AS a4,
SUM(CASE WHEN p.state =2 AND ce.id=4 THEN 1 ELSE 0 END ) AS n4,
SUM(CASE WHEN p.state =0 AND ce.id=5 THEN 1 ELSE 0 END ) AS v5,
SUM(CASE WHEN p.state =1 AND ce.id=5 THEN 1 ELSE 0 END ) AS a5,
SUM(CASE WHEN p.state =2 AND ce.id=5 THEN 1 ELSE 0 END ) AS n5
FROM cia_ensures ce
LEFT JOIN policies p on ce.id = p.cia_ensure_id
INNER JOIN policy_business_units pb ON pb.id = p.policy_business_unit_id
INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id
AND ca.id=1
Group by p.policy_business_unit_id;
The query is working fine without problems and showing this result:
UNIT V1 A1 N1 V2 A2 N2 V3 A3 N3 V4 A4 N4 V5 A5 N5
LIFE 2 0 0 1 2 0 0 0 0 0 0 0 0 0 0
ROB 0 1 0 0 1 2 0 0 0 0 0 0 0 0 0
But WHAT HAPPEN IF I HAVE 100 CIA_ENSURE? My query will be too long with more 100 lines. How can I do creating a value @value where i type my cia_ensure and this will repeat like this:
@cia_ensure_values = 1,3,5
for ce.id=1,3,5
/////This code will be repeated for all cias typed
SELECT pb.name as unit,
SUM(CASE WHEN p.state =0 AND ce.id=@cia_ensure_values THEN 1 ELSE 0 END ) AS v,
SUM(CASE WHEN p.state =1 AND ce.id=@cia_ensure_values THEN 1 ELSE 0 END ) AS a,
SUM(CASE WHEN p.state =2 AND ce.id=@cia_ensure_values THEN 1 ELSE 0 END ) AS n,
end
FROM cia_ensures ce
LEFT JOIN policies p on ce.id = p.cia_ensure_id
INNER JOIN policy_business_units pb ON pb.id = p.policy_business_unit_id
INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id
AND ca.id=1
Group by p.policy_business_unit_id;
Somebody can help me to optimize this query?
All kind of help will be accepted.
Please I will appreciate all kind of help.
Thanks.
Upvotes: 1
Views: 89
Reputation: 3266
You can easily accomplish this with a short prepared statement. Just include the ids you want in the where id in()
clause:
select distinct @sql := concat('SELECT pb.name as unit,',group_concat(concat(
'SUM(CASE WHEN p.state =0 AND ce.id=',id,' THEN 1 ELSE 0 END ) AS v',id,',
SUM(CASE WHEN p.state =1 AND ce.id=',id,' THEN 1 ELSE 0 END ) AS a',id,',
SUM(CASE WHEN p.state =2 AND ce.id=',id,' THEN 1 ELSE 0 END ) AS n',id)),
' FROM cia_ensures ce
LEFT JOIN policies p on ce.id = p.cia_ensure_id
INNER JOIN policy_business_units pb ON pb.id = p.policy_business_unit_id
INNER JOIN comercial_areas ca ON ca.id = pb.comercial_area_id
AND ca.id=1
Group by p.policy_business_unit_id;')
from cia_ensures
where id in(1,3,5);
prepare stmt from @sql;
execute stmt;
SQLFIDDLE: http://sqlfiddle.com/#!2/631b56/23
Upvotes: 1