Reputation: 153
I'm using media queries so I am passing the image to the html page from the external css file but the styling only works if I call the image directly from the html file but not from the external css file.
HTML code:
<img id="photo" class="photo-frame">
External css code:
#photo {
background: url('/images/example-photo.jpg') no-repeat;
width: 200px;
height: 200px;
}
.photo-frame {
float: left;
padding: 10px 10px 30px 10px;
background-color: #fff !important;
box-shadow: 2px 2px 3px #aaa;
transform: rotate(7deg);
-moz-transform: rotate(7deg);
-webkit-transform: rotate(7deg);
-o-transform: rotate(7deg);
-ms-transform: rotate(7deg);
}
So this is to make the photo look like a polaroid photo tilted to one side, the problem I get is the border is not showing white but just a line showing where the border starts. It works okay when I reference the photo from the HTML page and call the photo-frame class but not when I apply an id and pass over the image externally.
Upvotes: 1
Views: 174
Reputation: 76
Try to remove th !important
property from background-color
of photo-frame class and add !important
to background
property of #photo
in external css and also use div
tag instead of image
tag.
Upvotes: 0
Reputation: 1509
use <div id="photo" class="photo-frame">
whats happening in <img id="photo" class="photo-frame">
is there is no src
attribute so img tag becomes invalid. and secondly check if the url relative the stylesheet's location and not the html page's location. this is a common mistake
Upvotes: 1
Reputation: 640
Why not using a div-tag? And check if the url to the image is right. /images/... will refer to a directory on root level. ./images/... will refer to a directory in the same level as the css-file and ../images/... will refer to a directory in a level up from the directory with your css.
Upvotes: 1