CODEWITHSUNDEEP
c++
user3504402
user3504402

Reputation: 15

C++ getting integer instead of a float value

My problem is that when dividing two integers I can't get a float value. Here's the code

{
    cout << "Kokie skaiciai?" << endl;
    cin >> x;
    cin >> y;
    cout << "Atsakymas: " << dalyba(x, y) << endl;
}

and the function that i use

int dalyba (int x, int y)
{
float z;
z = (float) x / y;
return z;
}

so if x = 5 and y = 2 I get an answer 2 instead of 2.5. Any help would be apreciated.

Upvotes: 1

Views: 258

Answers (2)

Dan
Dan

Reputation: 5972

The return value of your dalyba function is an int. This should be a float.

float dalyba (int x, int y)
{
    float z;
    z = (float) x / y;
    return z;
}

Upvotes: 5

Mr.C64
Mr.C64

Reputation: 42934

The problem is that your function returns an int instead of a float, so the float result is cast back to an integer, and truncated. You may want to change the return value type of your function from int to float.

Moreover, in modern C++, you may want to use C++-style casts like static_cast<>.

The following snippet prints 2.5 as expected:

#include <iostream>
using namespace std;

float f(int x, int y) {
    return static_cast<float>(x) / y;
}

int main() {
    cout << f(5, 2) << endl;
}

Upvotes: 1

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