Reputation: 197
How to load the page only when such image is loaded? The base does not work, type:
$('#IDdaImagem').on('load',function(){
})
is a background image, and okay with a jquery plugin to open in other resolutions, the backstretch, it uses a div with class backstretch, as I carry this background image with 2mb before the contents of the site?
i test this and work, but not the item that I give show, appearing at the time, it works only in the alert.
<script>
$('.backstretch img').load(function() {
alert('done loading image');
$("#corpo").show();
});
</script>
Upvotes: 0
Views: 290
Reputation: 6720
Your example makes me think you don't want to "preload" an image necessarily, but want to wait until the image has been loaded before running a script. You can use something like the waitForImages jQuery plug-in for this.
https://github.com/alexanderdickson/waitForImages
Upvotes: 1
Reputation: 2365
Try code given below:
function preload(arrayOfImages) {
$(arrayOfImages).each(function(){
$('<img/>')[0].src = this;
// Alternatively you could use:
// (new Image()).src = this;
});
}
// Usage:
preload([
'img/imageName.jpg',
'img/anotherOne.jpg',
'img/blahblahblah.jpg'
]);
With Jquery plugin :
$.fn.preload = function() {
this.each(function(){
$('<img/>')[0].src = this;
});
}
// Usage:
$(['img1.jpg','img2.jpg','img3.jpg']).preload();
Upvotes: 0