CODEWITHSUNDEEP
pythonregexlistpython-2.7
VeilEclipse
VeilEclipse

Reputation: 2856

Use regular expression to remove contents in brackets in python

I have a list:

['14147618', '(100%)', '6137776', '(43%)', '5943229', '(42%)', '2066613', '(14%)', 'TOTAL']

also as as string '14147618 (100%) 6137776 (43%) 5943229 (42%) 2066613 (14%) TOTAL\n'

Using regex, how do I return:

['14147618', '6137776, '5943229', 2066613']

Upvotes: 1

Views: 109

Answers (6)

thefourtheye
thefourtheye

Reputation: 239473

You don't need RegEx at all, you can simply filter out the data which has only digits in them, with this list comprehension

print [item for item in data if item.isdigit()]
# ['14147618', '6137776', '5943229', '2066613']

Or you can also use filter builtin function, like this

print filter(str.isdigit, data)
# ['14147618', '6137776', '5943229', '2066613']

Edit: If you have the entire data as a single string, you can split the data based on whitespace characters and then use the same logic

data = '14147618 (100%)   6137776 (43%)   5943229 (42%)   2066613 (14%)  TOTAL\n'
print [item for item in data.split() if item.isdigit()]
# ['14147618', '6137776', '5943229', '2066613']
print filter(str.isdigit, data.split())
# ['14147618', '6137776', '5943229', '2066613']

Upvotes: 5

ooga
ooga

Reputation: 15501

Or if you want the even-indexed elements except for the last one:

print [data[i] for i in range(0,len(data)-1,2)]

Upvotes: 1

Nishant Nawarkhede
Nishant Nawarkhede

Reputation: 8400

No need to use re module at all , you can use filterover list.

Try this ,

>>> a=['14147618', '(100%)', '6137776', '(43%)', '5943229', '(42%)', '2066613', '(14%)', 'TOTAL']
>>> filter(str.isdigit, a)
['14147618', '6137776', '5943229', '2066613']
>>>

Upvotes: 2

sinceq
sinceq

Reputation: 924

Use re module:

>>> import re
>>> [item for item in s if re.match(r'\d+',item)]
['14147618', '6137776', '5943229', '2066613']

Upvotes: 2

NPE
NPE

Reputation: 500367

Here is one way:

>>> l = ['14147618', '(100%)', '6137776', '(43%)', '5943229', '(42%)', '2066613', '(14%)', 'TOTAL']
>>> [el for el in l if re.match(r'\d+$', el)]
['14147618', '6137776', '5943229', '2066613']

Upvotes: 2

Christian Tapia
Christian Tapia

Reputation: 34146

As @thefourtheye said, it's not necessary to use regex at all, but if you really want to do it with regex, you can use:

import re

a = ['14147618', '(100%)', '6137776', '(43%)', '5943229', '(42%)', '2066613', '(14%)', 'TOTAL']
result = []

for e in a:
    m = re.match(r'\d+', e)
    if m is not None:
        result.append(e)

print result
# ['14147618', '6137776', '5943229', '2066613']

Note: This can also be written as list comprehension:

print [e for e in a if re.match(r'\d+', e)]

Upvotes: 2

Related Questions