Reputation: 315
i have some meetings with date and hours and examinator, on these meetings, i put a candidate. The candidate must pass the exam.
i have a table like that:
Exam | Meeting | Niche | Date | Hour | Examinator | idCandidate
Math | 1 | 1 |2014-06-28|08:00 | John | 1
Math | 1 | 2 |2014-06-28|08:20 | John | 0
Math | 5 | 3 |2014-06-28|13:00 | John | 0
Math | 2 | 4 |2014-06-28|08:00 | Will | 0
Math | 2 | 5 |2014-06-28|08:20 | Will | 0
Math | 3 | 6 |2014-06-29|08:00 | John | 11
Math | 3 | 7 |2014-06-29|08:20 | John | 0
Math | 6 | 8 |2014-06-29|14:00 | John | 0
Bio | 4 | 9 |2014-06-28|08:00 | Bruce | 0
Bio | 4 | 10 |2014-06-28|08:20 | Bruce | 0
Bio | 4 | 11 |2014-06-28|08:40 | Bruce | 0
What i would like is:
Exam | Date | Examinator | Nb Free Candidate
Math |2014-06-28| John | 2
Math |2014-06-28| Will | 2
Math |2014-06-29| John | 2
Bio |2014-06-28| Bruce | 3
Actually, i want to display the number of free niche (meeting) order by exam, date and examinator.
Can you please help me?
Upvotes: 0
Views: 65
Reputation: 49039
You are probably looking for this GROUP BY query:
SELECT Exam, `Date`, Examinator, COUNT(*) AS nb_free_candidate
FROM tablename
WHERE idCandidate = 0
GROUP BY Exam, `Date`, Examinator
If your Date columns contains both date and time, you should use this instead:
SELECT Exam, DATE(`Date`), Examinator, COUNT(*) AS nb_free_candidate
FROM tablename
WHERE idCandidate = 0
GROUP BY Exam, DATE(`Date`), Examinator
Upvotes: 1