CODEWITHSUNDEEP
cintegercomparenewline
Lord Rixuel
Lord Rixuel

Reputation: 1243

How to compare an integer with newline in C?

I already know how to compare char type with newline (\n) but I would like to know how to compare an Integer with the newline (\n). Is it possible? (I did researches to find my answer but I end up getting answer that require char types)

I've the text file input with numbers:

11 22 33 44 55 1
2 3 4 56 777
1
255
3
5

I want the output to look like this

[11][22][33][44][55][1]<newline>[2][3][4][56][777]<newline>[1]<newline>[255]<newline>[3]<newline>[5]<newline>
lineNumber:[6]

but the output I get is 

[11][22][33][44][55][1][2][3][4][56][777][1][255][3][5]
lineNumber:[0]

This is the code I'm using

int *integers = malloc(sizeof(int) * 200);
int i=0, lineNumber=0, num=0;
//int num;

while(fscanf(file, "%d", &num) > 0) 
{       
    if(num == '\n'){
        printf("<newline>");
        lineNumber++;
    }

    integers[i] = num;

    printf("[%d]", integers[i]); // Just to show output.
    i++;
}
printf("\nlineNumber:[%d]", lineNumber);

Reason why I don't want to use the char type is because I've to re-convert the char digits into integer... I would like to care about the newline (\n) and integers only

Upvotes: 0

Views: 3130

Answers (1)

Musa
Musa

Reputation: 97717

You can attempt to read a newline character after each integer then check the return of fscanf to see how many items were read.

int *integers = malloc(sizeof(int) * 200);
int i=0, lineNumber=0, num=0;
int read;
char nl[2];

while((read=fscanf(file, "%d%[\n]", &num, &nl)) > 0) 
{       

    integers[i] = num;

    printf("[%d]", integers[i]); // Just to show output.
    i++;

    if(read == 2){
        printf("<newline>");
        lineNumber++;
    }
}
printf("\nlineNumber:[%d]", lineNumber);

Upvotes: 1

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