Reputation: 6193
I have a program where an object creates another object. However, the second object that gets created needs to be able to access the first. Is this possible?
EG (pseudocode)
class parentObject():
parentVar = 1
# Create Child
x = childObject()
class childObject():
#Assign Var to the Var of the childs parent
childVar = parent.parentVar
>>> x.childVar = 1
is there a straitforward way to do this?
UPDATE:
I don't want to inheret the class, I need to be able to access the actual object that created it, as each object created from that class has different values.
Upvotes: 0
Views: 53
Reputation: 7821
If you want a reference to the "parent" class, but inheritance is illogical, consider sending self
in to the constructor:
class Room:
def __init__(self, name):
self.name = name
self.furniture = []
def add_chair(self):
self.furniture.append(Chair(self))
def __str__(self):
return '{} with {}'.format(self.name, self.furniture)
class Chair:
def __init__(self, room):
self.room = room
def __str__(self):
return 'Chair in {}'.format(self.room.name)
r = Room('Kitchen')
r.add_chair()
r.add_chair()
print r
print r.furniture[0]
Output:
Kitchen with [<__main__.Chair instance at 0x01F45F58>, <__main__.Chair instance at 0x01F45F80>]
Chair in Kitchen
Upvotes: 1
Reputation: 32189
Why not inherit the class?
class parentObject():
parentVar = 1
class childObject(parentObject):
childVar = parentObject.parentVar
>>> x = childObject()
>>> print(x.childVar)
1
If you are going to have different instances of the class, you should do it as this instead:
class parentObject(object):
def __init__(self):
self.parentVar = 1
class childObject(parentObject):
def __init__(self):
super(childObject, self).__init__()
self.childVar = self.parentVar
>>> x = childObject()
>>> print(x.childVar)
1
Upvotes: 4