CODEWITHSUNDEEP
c++
Rockink
Rockink

Reputation: 180

Why can't I access directly in vector iterator?

Why can't i do like this? In the below code, I can access from for loop, but not from outside loop?

class root
{
    string name;

public:

    root()
    {
    }

    root(const string& okay)
    {
        name = okay;
    }

    void setRoot(const string& okay)
    {
        name = okay;
    }

    string getRoot()
    {
        return name;
    }

    ~root ()
    {
    }
}; // class root

int main()
{
    string a;
    vector<root> Root;
    vector<root>::iterator oley;
    root okay;

    for (int i=0; i<5;i++)   //this is to add strings in vector
    {
        cin >> a;
        okay.setRoot(a);
        Root.push_back(okay);
    }

    for (oley=Root.begin(); oley!=Root.end(); oley++)   //this is to print vectors in scren
    {
        cout << (*oley).getRoot() << endl;
    }
    oley = Root.begin();
    cout << (*oley + 2).getRoot();   //this is error. What is required to make it legal?

    return 0;
}

So, if we can access iterator from for loop, why can't we do so in non-looped codes?

cout << (*oley + 2).getRoot();

Upvotes: 1

Views: 55

Answers (1)

billz
billz

Reputation: 45410

This is because of C++ operator precedence, *oley+2 is interpreted as (*oley) + 2 which is becomes root + 2

update

cout<<(*oley+2).getRoot();

to

cout<<(*(oley+2)).getRoot();

or

cout<<oley[2].getRoot();

Upvotes: 4

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