CODEWITHSUNDEEP
sqlselectjoingroup-byinner-join
Rob4236
Rob4236

Reputation: 395

Trying to use INNER JOIN and GROUP BY SQL with SUM Function, Not Working

I am not getting my head around this, and wondered if anyone may be able to help me with this.

I have 2 Tables called RES_DATA and INV_DATA

RES_DATA Contains my Customer as below

CUSTOMER ID | NAME

1, Robert
2, John
3, Peter

INV_DATA Contains their INVOICES as Below

INVOICE ID | CUSTOMER ID | AMOUNT

100, 1, £49.95
200, 1, £105.95
300, 2, £400.00
400, 3, £150.00
500, 1, £25.00

I am Trying to write a SELECT STATEMENT Which will give me the results as Below.

CUSTOMER ID | NAME | TOTAL AMOUNT

1, Robert, £180.90
2, John, £400.00
3, Peter, £150.00

I think I need 2 INNER JOINS Somehow to Add the tables and SUM Values of the INVOICES Table GROUPED BY the Customer Table but honestly think I am missing something. Can't even get close to the Results I need.

Upvotes: 30

Views: 225257

Answers (5)

KIRAN REDDY
KIRAN REDDY

Reputation: 1

SELECT RES.[CUSTOMER ID], RES.NAME, SUM(INV.AMOUNT) AS [TOTAL AMOUNT]
FROM RES_DATA
JOIN INV_DATA ON RES.[CUSTOMER ID]=INV.[CUSTOMER ID]
GROUP BY RES.[CUSTOMER ID], RES.NAME

Upvotes: -2

chindirala sampath kumar
chindirala sampath kumar

Reputation: 651

If you need to retrieve more columns other than columns which are in group by then you can consider below query. Check it once whether it is performing well or not. 

SELECT 
a.[CUSTOMER ID], 
a.[NAME], 
(select SUM(b.[AMOUNT]) from INV_DATA b
where b.[CUSTOMER ID] = a.[CUSTOMER ID]
GROUP BY b.[CUSTOMER ID]) AS [TOTAL AMOUNT]
FROM RES_DATA a

Upvotes: 0

Hogan
Hogan

Reputation: 70523

Two ways to do it...

GROUP BY

SELECT RES.[CUSTOMER ID], RES,NAME, SUM(INV.AMOUNT) AS [TOTAL AMOUNT]
FROM RES_DATA RES
JOIN INV_DATA INV ON RES.[CUSTOMER ID] INV.[CUSTOMER ID]
GROUP BY RES.[CUSTOMER ID], RES,NAME

OVER

SELECT RES.[CUSTOMER ID], RES,NAME, 
       SUM(INV.AMOUNT) OVER (PARTITION RES.[CUSTOMER ID]) AS [TOTAL AMOUNT]
FROM RES_DATA RES
JOIN INV_DATA INV ON RES.[CUSTOMER ID] INV.[CUSTOMER ID]

Upvotes: 10

rory.ap
rory.ap

Reputation: 35310

This should work.

SELECT a.[CUSTOMER ID], a.[NAME], SUM(b.[AMOUNT]) AS [TOTAL AMOUNT]
FROM RES_DATA a INNER JOIN INV_DATA b
ON a.[CUSTOMER ID]=b.[CUSTOMER ID]
GROUP BY a.[CUSTOMER ID], a.[NAME]

I tested it with SQL Fiddle against SQL Server 2008: http://sqlfiddle.com/#!3/1cad5/1

Basically what's happening here is that, because of the join, you are getting the same row on the "left" (i.e. from the RES_DATA table) for every row on the "right" (i.e. the INV_DATA table) that has the same [CUSTOMER ID] value. When you group by just the columns on the left side, and then do a sum of just the [AMOUNT] column from the right side, it keeps the one row intact from the left side, and sums up the matching values from the right side.

Upvotes: 43

Hola Soy Edu Feliz Navidad
Hola Soy Edu Feliz Navidad

Reputation: 7072

Use subquery

SELECT * FROM RES_DATA inner join (SELECT [CUSTOMER ID], sum([TOTAL AMOUNT]) FROM INV_DATA group by [CUSTOMER ID]) T on RES_DATA.[CUSTOMER ID] = t.[CUSTOMER ID]

Upvotes: 3

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