Reputation: 9
Need to check if both the EMAIL_ADDRESS
and ACTIVATION_CODE
exist within a MySql Table, if so return "Code is valid"
,else "Code is NOT valid"
.
At present it's always returning code not valid, however I've checked the record in the table and the queried code does exist.
$email = $_POST['email'];
$acticode = $_POST['code'];
$result = mysql_query("SELECT * FROM xActivate WHERE EMAIL_ADDRESS='$email' AND ACTIVATION_CODE='$acticode' LIMIT 1");
if (mysql_fetch_row($result)) {
echo 'Code is valid';
} else {
echo 'Code is NOT valid';
}
Upvotes: 0
Views: 216
Reputation: 7769
But this code is not secure:
$email = $_POST['email'];
$acticode = $_POST['code'];
$result = mysql_query("SELECT * FROM xActivate WHERE EMAIL_ADDRESS='$email' AND ACTIVATION_CODE='$acticode' LIMIT 1");
$data = mysql_fetch_row($result);
if (mysql_num_rows($result) > 0) {
echo 'Code is valid';
} else {
echo 'Code is NOT valid';
}
To secure and prevent SQL Injection:
$email = mysql_real_escape_string($_POST['email']);
$acticode = mysql_real_escape_string($_POST['code']);
Please note:
https://www.php.net/mysql_real_escape_string
Warning
This extension is deprecated as of PHP 5.5.0, and will be removed in the future. Instead, the MySQLi or PDO_MySQL extension should be used. See also MySQL: choosing an API guide and related FAQ for more information. Alternatives to this function include:
mysqli_real_escape_string() PDO::quote()
Upvotes: 3