Reputation: 824
Hey guys this is my db : http://prntscr.com/39on8i
I get this error if I try to add something to my users1 table : Unknown Column Nume in 'field list'
This is my VB code :
'INSERT INTO config (id, customer_id, domain) 'SELECT DISTINCT id, customer_id, domain FROM config;'
Try
' Dim SqlQuery As String = "INSERT INTO presence(id_presence,id,hours,date) " & _
' "SELECT DISTINCT @Id_presence,@Id,@Hours,@Date FROM presence"
'adding a new user
Dim SqlQuery As String = "INSERT INTO users1(id,Nume,Prenume,username,password,onedrive,access, id_dep, id_pontaj) " & _
"VALUES (0,@Nume,@Prenume,@Username,@Password,@Onedrive,@Access,@Iddep,@Idpontaj)"
Using con = New MySqlConnection("Server = localhost;Database = accounts; Uid=root; Pwd = password")
Using SQLcmd = New MySqlCommand(SqlQuery, con)
con.Open()
'SQLcmd.ExecuteNonQuery()
'SQLcmd.Parameters.AddWithValue("@Id_presence", Convert.ToInt32(TextBox1.Text))
'SQLcmd.Parameters.AddWithValue("@Id", Convert.ToInt32(TextBox2.Text))
'SQLcmd.Parameters.AddWithValue("@Hours", Convert.ToInt32(TextBox3.Text))
'SQLcmd.Parameters.AddWithValue("@Date", Convert.ToDateTime(TextBox4.Text))
SQLcmd.Parameters.AddWithValue("@Nume", Convert.ToString(TextBox2.Text))
SQLcmd.Parameters.AddWithValue("@Prenume", Convert.ToString(TextBox3.Text))
SQLcmd.Parameters.AddWithValue("@Username", Convert.ToString(TextBox4.Text))
SQLcmd.Parameters.AddWithValue("@Password", Convert.ToString(TextBox5.Text))
SQLcmd.Parameters.AddWithValue("@Onedrive", Convert.ToString(TextBox6.Text))
SQLcmd.Parameters.AddWithValue("@Access", Convert.ToInt32(TextBox1.Text))
SQLcmd.Parameters.AddWithValue("@Iddep", Convert.ToInt32(TextBox7.Text))
SQLcmd.Parameters.AddWithValue("@Idpontaj", Convert.ToString(TextBox8.Text))
SQLcmd.ExecuteNonQuery()
End Using
End Using
Catch ex As Exception
MsgBox(" Failure to communicate " & vbCrLf & vbCrLf & ex.Message)
End Try
Upvotes: 1
Views: 225
Reputation: 2522
It could be that the ID is being seen as reserved (not sure why), but try and put square brackets around it in the field list [id]
Upvotes: 1