CODEWITHSUNDEEP
pythonlambda
Leon
Leon

Reputation: 6544

Short code: map, filter, lambda

I use Python 3.4 and I have this code:

result = []
    for i in r['resp']:
        for id in self.all_dicts:
            if i == id['id']:
                result.append(id)

Its very long, so I want to short:

result = list(map(filter(lambda x: x == i,self.all_dicts),r['resp']))

But I have an error:

TypeError: 'filter' object is not callable

How to fix that? Thanks

Upvotes: 0

Views: 123

Answers (1)

jonrsharpe
jonrsharpe

Reputation: 122061

I think you want:

result = [id for id in self.dicts if id['id'] in r['resp']]

Upvotes: 3

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