Reputation: 51
i just write another radix sort program, here is my code:
#----------radix sort----------
def set_output():
output_list = []
for i in range (10):
output_list.append(queue())
return output_list
def set_radix(lists):
output_list = set_output()
for queue in lists:
for num in queue:
a = num[2]
output_list[int(a)].add(num)
return output_list
def sec_radix(input_list, i):
output_list = set_output()
for queue in input_list:
while len(queue) > 0:
num = queue.after()
a = num[i]
output_list[int(a)].add(num)
return output_list
def done_radix(num_list):
return sec_radix(sec_radix(set_radix(num_list), 1), 0)
the python shell keeps telling me that "IndexError: string index out of range", my string of numbers is all right. i think something wrong with my def set_radix()
function, but i can't find out where is it?
Upvotes: 0
Views: 7120
Reputation: 21630
Here is a radix sort coded so someone reasonable can understand it. I stole most of it from here.
def radixsort( aList ):
RADIX = 10
maxLength = False
tmp , placement = -1, 1
while not maxLength:
maxLength = True
# declare and initialize buckets
buckets = [list() for _ in range( RADIX )]
# split aList between lists
for i in aList:
tmp = i // placement
print ("i is " , i)
print ("placement is " , placement)
print ("tmp is ", tmp)
print ("tmp % RADIX is ", tmp % RADIX)
buckets[tmp % RADIX].append( i )
if maxLength and tmp > 0:
maxLength = False
# empty lists into aList array
a = 0
for b in range( RADIX ):
buck = buckets[b]
for i in buck:
aList[a] = i
a += 1
# move to next digit
placement *= RADIX
return aList
a = radixsort([18,5,100,3,1,19,6,0,7,4,2])
print(a)
The code on the site I got it from had some issues arising from % yielding a float. I suspect differences from python 2 to 3.
Upvotes: 2