CODEWITHSUNDEEP
javastringabstract-class
Apprentice Programmer
Apprentice Programmer

Reputation: 1515

how to print object value with String method

I have an abstract class like this 

public abstract class Temperature

{

private float value;
public Temperature(float v)
{
    value = v;
}

public final float getValue()
{
    return value;
}

public abstract Temperature toCelsius();
public abstract Temperature toFahrenheit();
public abstract Temperature toKelvin();
}

then I have classes that extend this Temperature class, example:

 public class Celsius extends Temperature
{
public Celsius(float t)
{
    super(t);
}


public String toString()
{
    return "";
}


@Override
public Temperature toCelsius() {
    // TODO Auto-generated method stub
    return this;
}

public Temperature toKelvin(){
    return new Kelvin(this.getValue() + 273);
}

@Override
public Temperature toFahrenheit() {
    // TODO Auto-generated method stub
    return new Fahrenheit(this.getValue() * 9 / 5 +32);
}

}

main method creates objects of of Celcius

     Temperature inputTemp = null, outputTemp = null;

     inputTemp = new Celsius(temp_val);

     outputTemp = inputTemp.toCelsius();

then prints the object by calling this method

     System.out.println("\n The converted temperature is " + outputTemp.toString() +"\n\n");
    }

What do i have to put in the toString method in order to print the desired value? this.super.getValue() didnt work and im kinda clueless. Since we are not going to be returning the same object everytime, dont we have to use the superclass?

Upvotes: 0

Views: 182

Answers (2)

JB Nizet
JB Nizet

Reputation: 692003

this.super is invalid syntax. super is not a field of this. It's a keyword that allows calling the superclass implementation of a method rather than calling the overridden implementation, from the current class. You just need

return Float.toString(this.getValue());

or 

return Float.toString(getValue());

or even

return Float.toString(super.getValue());

But using super.getValue() is useless, since the subclass doesn't override the base getValue() method, and you thus don't need to explicitely use the super implementation of the method.

Upvotes: 0

Szymon
Szymon

Reputation: 43023

It will be enough if you use:

public String toString()
{
    return Float.toString(this.getValue());
}

Upvotes: 1

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