CODEWITHSUNDEEP
javaphphashsha256
user2663561
user2663561

Reputation: 123

SHA256 in PHP & Java

I'm porting some Java code to PHP code. In Java I have a hash SHA256 code as below:

public static String hashSHA256(String input)
        throws NoSuchAlgorithmException {
    MessageDigest mDigest = MessageDigest.getInstance("SHA-256");

byte[] shaByteArr = mDigest.digest(input.getBytes(Charset.forName("UTF-8")));
    StringBuilder hexStrBuilder = new StringBuilder();
    for (int i = 0; i < shaByteArr.length; i++) {
        hexStrBuilder.append(Integer.toHexString(0xFF & shaByteArr[i]));
    }

    return hexStrBuilder.toString();
}

In PHP, I hash as below:

$hash = hash("sha256", utf8_encode($input));

I run the sample code with both input = "test". However, I got 2 hash strings which are not the same:

Java: 9f86d081884c7d659a2feaa0c55ad015a3bf4f1b2bb822cd15d6c15b0f0a8
PHP: 9f86d081884c7d659a2feaa0c55ad015a3bf4f1b2b0b822cd15d6c15b0f00a08

Can someone explain to me why and how to get them match each other? Please note that I cannot modify the Java implementation code, only to modify PHP.

Really appreciate!

Upvotes: 4

Views: 7177

Answers (2)

Giang Le
Giang Le

Reputation: 11

The PHP version is correct. But we can modify the result to have the same result with java code.

function hash256($input) {
    $hash = hash("sha256", utf8_encode($input));
    $output = "";
    foreach(str_split($hash, 2) as $key => $value) {
        if (strpos($value, "0") === 0) {
            $output .= str_replace("0", "", $value);
        } else {
            $output .= $value;
        }
    }
    return $output;
}

echo hash256("test");

result: 9f86d081884c7d659a2feaa0c55ad015a3bf4f1b2bb822cd15d6c15b0f0a8

Upvotes: 1

George Brighton
George Brighton

Reputation: 5151

The PHP version is correct; the SHA-256 checksum of test is 9f86d081884c7d659a2feaa0c55ad015a3bf4f1b2b0b822cd15d6c15b0f00a08.

The Java version is returning the same checksum with two 0s stripped out. This is because of the way you're converting bytes into hex. Instead of &ing them with 0xFF, use String.format(), as in this answer:

hexStrBuilder.append(String.format("%02x", shaByteArr[i]));

I realise you say you cannot modify the Java code, but it is incorrect!

Upvotes: 7

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