CODEWITHSUNDEEP
pythonarrayslistreplacetuples
taytortot
taytortot

Reputation: 99

Replace String From Tuple Inside List

I currently have the following list:

data = [('b','..','o','b'),('t','s','..','t')]

I am trying to figure out a way to replace all instances of the '..' string to another string. In my instance, the string of ' '.

I have attempted to use the built-in function using the following method, but had no luck.

newData = list(map(lambda i: str.replace(i, ".."," "), data))

Could someone point me in the right direction? My desired output would be the following:

newData = [('b',' ','o','b'),('t','s',' ','t')]

Upvotes: 5

Views: 15915

Answers (2)

joc
joc

Reputation: 1088

Map operates on each of the elements of the list given. So in this case, your lambda expression is being called on a tuple, not the elements of the tuple as you intended.

wrapping your code in a list comprehension would do it:

newData = [tuple(map(lambda i: str.replace(i, ".."," "), tup)) for tup in data]

Upvotes: 3

user2555451
user2555451

Reputation:

You can use a list comprehension with a conditional expression:

>>> data = [('b','..','o','b'),('t','s','..','t')]
>>> newData = [tuple(s if s != ".." else " " for s in tup) for tup in data]
>>> newData
[('b', ' ', 'o', 'b'), ('t', 's', ' ', 't')]
>>>

Upvotes: 3

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