CODEWITHSUNDEEP
java
maxxtack
maxxtack

Reputation: 11

Dynamic arrays without vector in java

import java.util.Scanner;

public class Test {
 public static void main(String[] args) {
  Scanner sc = new Scanner(System.in);
  int n = sc.nextInt();
  int[] v = new int[n];
 }
}

Is there any problem in doing this?

Upvotes: 0

Views: 275

Answers (3)

Drahakar
Drahakar

Reputation: 6078

The good thing using class like vector is that it encapsulate all the management you need to do with your array. So, as Tom Hawtin - tackline said, it would manage unexpected value but it will also manage resize, and it will provide you some usefull method to deal with your array, like .get witch will disallow you to get an item out of bound and many more method you can get there : http://java.sun.com/j2se/1.4.2/docs/api/java/util/Vector.html

btw, as a side note I would recommand you to use an ArrayList : http://java.sun.com/j2se/1.4.2/docs/api/java/util/ArrayList.html

Upvotes: 0

Tom Hawtin - tackline
Tom Hawtin - tackline

Reputation: 147154

No. (Other than n might be negative, or be huge causing a Denial-of-Service (DoS) condition.)

With arrays you can't change the size later. You have to create a new array, copy the contents and switch all references over.

Upvotes: 3

Matthew Flaschen
Matthew Flaschen

Reputation: 284786

No, but unlike Vector it is obviously not resizable. Note that in Java, all collections are allocated on the heap.

Upvotes: 0

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