CODEWITHSUNDEEP
sed
nikita.zhelonkin
nikita.zhelonkin

Reputation: 637

Sed select value of parameter

I need to extract value using sed command; I have a file, that contains something like this:

field="value"

The result needs to be: value

Upvotes: 0

Views: 139

Answers (3)

Bruce Barnett
Bruce Barnett

Reputation: 948

Or you can use awk to look for "field", split the fields up using '=', and then deleting the extra quotes using tr

awk -F= '/field/ {print $2}' <file | tr -d '"'

Upvotes: 0

mklement0
mklement0

Reputation: 439397

Just to provide an awk alternative, since awk is often the better choice when it comes to field-based processing.

Your exact requirements are unclear, but here I'm making the following assumptions:

  • field names are unique
  • there are no spaces around the = and all values are "-enclosed

The following allows you to pass in a field name via the -v fname=... option and returns that field's value unquoted; sample input is provided via a here-document.

awk -F\" -v fname='field' '$1 == (fname "=") { print $2; exit }' <<'EOF'
key="largo"
field="value"
id="fake"
EOF

Upvotes: 0

Bruce Barnett
Bruce Barnett

Reputation: 948

try

#!/bin/sh                                                                                                                                    
sed -n 's/field="\(.*\)"/\1/p'

This looks for lines that have field=

If it finds them, it removes everything except the value, and prints the value. Otherwise, it prints nothing.

Upvotes: 4

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