Reputation: 21
I want to make a dropdown list that creates a new dropdown list dependent on the options made. I can do it in HTML using JavaScript using the following:
<div>
<legend> Question </legend>
<select class="source" id="selType">
<option>Select</option>
<option value="A1"> Answer1 </option>
<option value="A2"> Answer2 </option>
<option value="A3"> Answer3 </option>
</select>
</div>
<div id="Answers">
<div id="A1" style="display: none;">
<select id="Option1">
<label>Select Workshop</label>
<option value="1"> 1 </option>
<option value="2"> 2 </option>
<option value="3"> 3 </option>
</select>
</div>
<div id="A2" style="display: none;">
<select id="Option2">
<-- list items -->
</select>
</div>
<div id="A3" style="display: none;">
<select id="Option3">
<-- list items -->
</select>
</div>
</div>
<script>
$(function () {
$('#selType').change(function () {
$('#Answers > div').hide();
$('#Answers').find('#' + $(this).val()).show();
});
});
</script>
However, I can't seem to do the same using 2 lists made through data acquired with MySQL in PHP; as follows.
// Pull data for cluster names
$query="SELECT LIST_OF_CLUSTERS.CLUSTER_NAME
FROM LIST_OF_CLUSTERS";
$data = mysqli_query($db_connect, $query) or die(mysqli_error());
// Create drop down list of cluster names
echo "<label>Location</label>";
echo "<select class='form-control' name='location1'>";
echo "<option value='All'>All</option>";
$number_results = mysqli_num_rows($data);
while($results = mysqli_fetch_array($data)){
echo "<OPTION value='". $results['CLUSTER_NAME'] ."'>" . $results['CLUSTER_NAME'] . "</option>";
}
echo "</select>";
// Pull data for university names
$query="SELECT LIST_OF_UNIVERSITIES.UNIVERSITY_NAME
FROM LIST_OF_UNIVERSITIES
ORDER BY LIST_OF_UNIVERSITIES.UNIVERSITY_NAME";
$data = mysqli_query($db_connect, $query) or die(mysqli_error());
// Create drop down list of cluster names
echo "<label>University</label>";
echo "<select class='form-control' name='university1'>";
echo "<option value='All'>All</option>";
$number_results = mysqli_num_rows($data);
while($results = mysqli_fetch_array($data)){
echo "<OPTION value='". $results['UNIVERSITY_NAME'] ."'>". $results['UNIVERSITY_NAME'] . "</option>";
}
echo "</select>";
In the database the university names are organised in clusters (north, south, east west etc) and the current code does a good job making a list of clusters and a list of universities (both of which starting with "All"), but with no correlation to each other. I tried to implement the JavaScript above through various id tags and trying to split the PHP up with but to no avail.
The university array in the database contains a value for each of the entries called "Cluster" which equals various numbers depending on which cluster they are in (0,1,2 etc) and I can make the list only show universities from the cluster by adding WHERE CLUSTER='n' to the following, so it's easy enough to create the lists I need, I just cant make them appear only when required;
// Pull data for uni names - South West
$query="SELECT LIST_OF_UNIVERSITIES.UNIVERSITY_NAME
FROM LIST_OF_UNIVERSITIES
WHERE CLUSTER='2'
ORDER BY LIST_OF_UNIVERSITIES.UNIVERSITY_NAME";
Any help would be much appreciated :)
Upvotes: 1
Views: 9125
Reputation: 824
**Full Code with MVC dependent Drop down using Ajax **
<div class="col-md-4" id="cars_reff_idedt">
<select name="cars_reff_id" id="edtcars_reff_id" class="col-md-12" >
<option value="">--Select Car--</option>
<?php
foreach ($car as $new) {
$sel = "";
if (set_select('cars_reff_id', $new->id))
$sel = "selected='selected'";
echo '<option value="' . $new->id . '" ' . $sel . '>' . $new->name . '</option>';
}
?>
</select>
</div>
<div class="col-md-4" id="chasis_id">
<select name="chasis_id" id="chasis_id" class="col-md-12" > </select>
</div>
<script>
//Dependent DropDown Car+Chessis
$(document).on('change', '#edtcars_reff_id', function () {
vch = $(this).val();
if (vch) {
$.ajax({
url: '<?php echo site_url('admin/expense/getChessisNo') ?>',
dataType: 'Json',
data: {'id': vch},
success: function (data) {
$('select[name="chasis_id"]').empty();
$.each(data, function (key, value) {
$('select[name="chasis_id"]').append('<option value="' + key + '">' + value + '</option>');
});
}
});
} else {
$('select[name="city"]').empty();
}
});
</script>
<?php
function getChessisNo() {
$data = $this->car_model->getChessisByCarId($_GET['id']);
$json = [];
foreach ($data as $row) {
$json[$row->id] = $row->number;
}
echo json_encode($json);
}
?>
Upvotes: 0
Reputation: 21
Never mind, I got it in the end.
All it required was putting the php part inside the select bracket, which seems so obvious now. I guess I was just having a blank day :)
<div>
<label>University?</label>
<select class= "source form-control" id="selUni" name="university1">
<option>Select</option>
<option value='All'>All</option>
<?php
$number_results = mysqli_num_rows($data);
while($results = mysqli_fetch_array($data)){
echo "<OPTION value=\"". $results['UNIVERSITY_NAME'] . "\">". $results['UNIVERSITY_NAME'] . "</option>";
}
?>
</select>
</div>
Upvotes: 1