CODEWITHSUNDEEP
lualogic
Mojimi
Mojimi

Reputation: 3151

How to choose the closest value comparing a table with a number?

Basically i have this function that will move an item, tile to tile until it reaches a certain position

but this item can only be moved 1 tile at a time

for i= -1, 1 , 2 do -- getting surrounding tiles

           Surrounding_tiles.x = original_pos.x+(i)
           Surrounding_tiles.y = original_pos.y+(i)
-- checking which surrounding tiles are not obstructed

 if Map.IsTileWalkable(Surrounding_tiles.x,Surrounding_tiles.y,original_pos.z)

        then 
-- moving to tile
        Map.MoveItem(xfrom, yfrom, xto, yto,)
 end
end

there's just a problem here, after selecting the not obstructed tiles, i need it to select the one tile(x and y) that is closest to the final position i want it to go

final_position.x
final_position.y

The "map" is a simple grid with no negative values

if this is too complicated and would require to make a pathfinding function then nevermind^^

Upvotes: 1

Views: 539

Answers (1)

Colonel Thirty Two
Colonel Thirty Two

Reputation: 26549

A simple solution:

local final_position
-- set final position to something

-- Define a distance function that takes a grid position
-- and returns the distance to the final position
local distance = function(start)
    return math.abs(start.x - final_position.x) + math.abs(start.y - final_position.y)
end

-- Define a comparator that compares locations based on
-- distance to final position
local comparator = function(a, b)
    return distance(a) < distance(b)
end

local adj_tiles
-- Set adj_tiles to an array of grid positions

table.sort(adj, comparator) -- Sort adjacent tiles based on distance

local nearest = adj[1] -- Closest is now the first item in the array

Upvotes: 1

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