CODEWITHSUNDEEP
macosbashmakefile
Morgan Wilde
Morgan Wilde

Reputation: 17323

Bash script to open executable in a new terminal

My intent is to automate the compilation process in my workflow. I have a single Makefile in the root directory and I find myself constantly typing in make to see the result and then SIGTERM to refresh (I'm running OS X 10.8.5). Whereas ideally, a bash script would listen for changes in the file, and automake when they are made, and then run the executable.

I have the following attempt at implementing a bash script.

#!/bin/bash

while true
do
    ATIME=`stat library/grid.c | egrep -o -m 3 '"(.{20})"' | tail +4`

    if [[ "$ATIME" != "$LTIME" ]]
    then
        echo "Running make..."
        bash -e make; ./sheet
        LTIME=$ATIME
    fi
    sleep 1
done

This results in the following errors

/usr/bin/make: /usr/bin/make: cannot execute binary file
./listener.sh: line 10: ./sheet: No such file or directory

How do I issue the command to make and run an executable in a new terminal window? The point of this is that I can keep my bash script running, listening for changes in the background, without the executable taking over.

Upvotes: 0

Views: 471

Answers (1)

MadScientist
MadScientist

Reputation: 100986

It's not legal to run bash -e <cmd> for any command, not just make. The argument given to bash is expected to be a shell script, not a program.

I don't know why you're trying to use a shell like that; why not just run make directly? But if you really want to run make in bash you'll have to use the -c flag.

If what you want to do is stop your script if make fails, then use:

make || exit 1
./sheet

If you want to keep going after an error but not run the command, then use:

make && ./sheet

Upvotes: 1

Related Questions