CODEWITHSUNDEEP
bashshellif-statementscripting
user3524591
user3524591

Reputation: 21

Unexpected tokens, syntax error on if statement,

I am having a problem with my if statement, for some reason it will not run. here is the code: 

if (( $digit1 -ne $digit2 )); then
 echo "test"

fi

I get this error message: line 32: ((: 1 -ne 2 : syntax error in expression (error token is "2 ")

** I have digit set to 2

Upvotes: 0

Views: 166

Answers (2)

iamauser
iamauser

Reputation: 11469

As @devnull said and adding to that, use :

 if [ $digi1 -ne $digi2 ]; then
   echo "Unequal numbers"
 fi

Upvotes: 1

devnull
devnull

Reputation: 123458

You are using the form:

((expression))

which evaluates the expression according to the rules of Arithmetic Evalution.

You have two options. Either fix the operator, i.e. use !=:

if (( d1 != d2 )); then

or use test:

if [ $d1 -ne $d2 ]; then

If you're using the arithmetic context:

    !, ~        logical and bitwise negation

Quoting from help test:

  arg1 OP arg2   Arithmetic tests.  OP is one of -eq, -ne,
                 -lt, -le, -gt, or -ge.

Upvotes: 1

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