CODEWITHSUNDEEP
c#c++
Davide I.
Davide I.

Reputation: 302

vector of string in c#

I'm here to ask you help with a code i'm working on.

I'm converting a tool from C++ to C#.

I've almost completed everything, but...

There's the code in C++ of Struct and how the tool use it:

struct Line
{
    uint16_t Magic;
    std::vector<std::string> Params;
}

This is the structure, the tool use like this in a switch:

case MAGIC_FUNCTION_BEGIN:
{
    pLine -> Params[0][8] = ' ';
    Output << pLine -> Params[0];
    pLine -> Params.erase(pLine->Params.begin());
    Output << GenParams(pLine->Params) << '\n';
    break;
}

So, now, the question is:

How is possible that use pLine -> Params[0][8] if it is a simple string vector?

Thanks!

Thank you so much for the answer.

I resolved in C# by setting it as:

char[] text = pLine.param[0].ToCharArray();
text[8] = ' ';
pLine.param[0] = text.ToString();

Now i've to ask something else about this code...

What it means when it does 

pLine -> Params.erase(pLine->Params.begin());

How can be converted to C# something like erase and begin?

Thanks :)

Upvotes: 0

Views: 1170

Answers (2)

Vlad from Moscow
Vlad from Moscow

Reputation: 310950

The type of expression Params[0] is reference to an object of type std::string. Shortly speaking Params[0] is an object of type std::string and applying the second subscript operator Params[0][8] you will get the character at position 8.

That it would be more clear you could split statement

pLine -> Params[0][8] = ' ';

into two statements

std::string &s = pLine -> Params[0];
s[8] = ' ';

In fact you have two containers where one container is put in another container.

Upvotes: 0

Yirkha
Yirkha

Reputation: 13818

std::string has an operator[] for accessing the individual elements.

pLine->Params[0][8] means "access the 9th character of the first parameter in pLine". In this case, it's set to a space character ''.

Upvotes: 1

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