Reputation: 3491
I have a table with user items. Each user may have several types of items, and may have each item more than once. I want to see how many items of each type each user have. So I use the following query:
select user_name, count(item_name) as "count_item", item_name
from my_table
group by user_name, item_name
order by user_name, count_item desc;
So I get something like this:
user_name | count_item | item_name
----------+-------------+-----------
User 1 | 10 | item X
User 1 | 8 | item Y
User 2 | 15 | item A
User 2 | 13 | item B
User 2 | 7 | item C
User 2 | 2 | item X
etc.
Now, I want to see only the first 3 items of each user. In the above example, for User 1 I want to see item X and Y, and for User 2 I want to see items A, B and C.
How can I acheieve this?
Thanks!
Upvotes: 11
Views: 871
Reputation: 5622
Use PARTITION BY. Something like this should work:
select user_name, count_item, item_name
from (select user_name, count(item_name) as "count_item", item_name
row_number() over (partition by user_name order by count_item desc)
from my_table)
where row_number < 4
group by user_name, item_name
order by user_name, count_item desc;
Upvotes: 3
Reputation: 37029
Unfortunately, I don't have Postgres to hand to test this, but a query like the following should get you to the results that you want.
select user_name, item_name, item_count from
(
select user_name, item_name, count(item_name) as item_count,
dense_rank() over (order by count(item_name) desc) as item_rank
from my_table
group by user_name, item_name
)
where item_rank <= 3;
Upvotes: 0