CODEWITHSUNDEEP
pythonpython-2.7python-3.x
Zach Gates
Zach Gates

Reputation: 4155

How do I call function inside another function?

If I have two functions, (one inside the other);

def test1():
    def test2():
        print("test2")

How do I call test2?

Upvotes: 1

Views: 188

Answers (3)

Victor Martins
Victor Martins

Reputation: 769

You can call it in this way too:

def test1():
    text = "Foo is pretty"
    print "Inside test1()"
    def test2():
        print "Inside test2()"
        print "test2() -> ", text
    return test2

test1()() # first way, prints "Foo is pretty"

test2 = test1() # second way
test2() # prints "Foo is pretty"

Let's see:

>>> Inside test1()
>>> Inside test2()
>>> test2() ->  Foo is pretty

>>> Inside test1()
>>> Inside test2()
>>> test2() ->  Foo is pretty

If you don't want to call the test2():

test1() # first way, prints "Inside test1()", but there's test2() as return value.
>>> Inside test1()
print test1()
>>> <function test2 at 0x1202c80>

Let's get more hard:

def test1():
    print "Inside test1()"
    def test2():
        print "Inside test2()"
        def test3():
            print "Inside test3()"
            return "Foo is pretty."
        return test3
    return test2

print test1()()() # first way, prints the return string "Foo is pretty."

test2 = test1() # second way
test3 = test2()
print test3() # prints "Foo is pretty."

Let's see:

>>> Inside test1()
>>> Inside test2()
>>> Inside test3()
>>> Foo is pretty.

>>> Inside test1()
>>> Inside test2()
>>> Inside test3()
>>> Foo is pretty.

Upvotes: 3

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 799370

You can't, since test2 stops existing once test1() has returned. Either return it from the outer function or only ever call it from there.

Upvotes: 0

sredmond
sredmond

Reputation: 460

def test1():
  def test2():
    print "Here!"
  test2() #You need to call the function the usual way

test1() #Prints "Here!"

Note that the test2 function is not available outside of test1. If, for instance, you tried to call test2() later in your code, you would get an error.

Upvotes: 3

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