Reputation: 10589
im working right now on a problem with edges.
i created this edge type in a graph without transactions:
this.graph.createEdgeType("edge", null);
So there is now an edge type edge
with the parent E
.
When i now create an edge of the created edge type (in a graph with transactions):
Edge edge = this.graph.addEdge("class:edge", outVertex, inVertex, "example");
and add a property to it:
edge.setProperty("property", "example");
He is creating a new class example
as subclass of E
:
WARNING: Committing the active transaction to create the new type 'example'
as subclass of 'E'. The transaction will be reopen right after that.
To avoid this behavior create the classes outside the transaction.
Why is he not taking my edge
type which i created as superclass
of the example
edge?
Why is he creating a new type as subclass of E
?
I do the same thing with Vertices but the difference is it works:
this.graph.createVertexType("person", null);
Vertex vertex = this.graph.addVertex("class:person", null, "person");
vertex.setProperty("name", "peter");
No problem here.
Upvotes: 0
Views: 706
Reputation: 9060
Use the edge's label as class.:
Edge edge = this.graph.addEdge("class:example", outVertex, inVertex, "example");
Upvotes: 1