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javainheritanceconstructorsuperclass
Anil
Anil

Reputation: 461

how to inherit Constructor from super class to sub class

How to inherit the constructor from a super class to a sub class?

Upvotes: 44

Views: 131456

Answers (6)

Java Main
Java Main

Reputation: 1581

You inherit class attributes, not class constructors .This is how it goes :

If no constructor is added in the super class, if no then the compiler adds a no argument contructor. This default constructor is invoked implicitly whenever a new instance of the sub class is created . Here the sub class may or may not have constructor, all is ok .

if a constructor is provided in the super class, the compiler will see if it is a no arg constructor or a constructor with parameters.

if no args, then the compiler will invoke it for any sub class instanciation . Here also the sub class may or may not have constructor, all is ok .

if 1 or more contructors in the parent class have parameters and no args constructor is absent, then the subclass has to have at least 1 constructor where an implicit call for the parent class construct is made via super (parent_contractor params) .

this way you are sure that the inherited class attributes are always instanciated .

Upvotes: 1

MSingh
MSingh

Reputation: 627

Superclass constructor CAN'T be inherited in extended class. Although it can be invoked in extended class constructor's with super() as the first statement.

Upvotes: 15

MCory
MCory

Reputation: 437

Default constructors -- public constructors with out arguments (either declared or implied) -- are inherited by default. You can try the following code for an example of this:

public class CtorTest {
    public static void main(String[] args) {
        final Sub sub = new Sub();
        System.err.println("Finished.");
    }

    private static class Base {
        public Base() {
            System.err.println("In Base ctor");
        }
    }

    private static class Sub extends Base {
        public Sub() {
            System.err.println("In Sub ctor");
        }
    }
}

If you want to explicitly call a constructor from a super class, you need to do something like this:

public class Ctor2Test {
    public static void main(String[] args) {
        final Sub sub = new Sub();
        System.err.println("Finished.");
    }

    private static class Base {
        public Base() {
            System.err.println("In Base ctor");
        }

        public Base(final String toPrint) {
            System.err.println("In Base ctor.  To Print: " + toPrint);
        }
    }

    private static class Sub extends Base {
        public Sub() {
            super("Hello World!");
            System.err.println("In Sub ctor");
        }
    }
}

The only caveat is that the super() call must come as the first line of your constructor, else the compiler will get mad at you.

Upvotes: 7

Andrew Hare
Andrew Hare

Reputation: 351758

Constructors are not inherited, you must create a new, identically prototyped constructor in the subclass that maps to its matching constructor in the superclass.

Here is an example of how this works:

class Foo {
    Foo(String str) { }
}

class Bar extends Foo {
    Bar(String str) {
        // Here I am explicitly calling the superclass 
        // constructor - since constructors are not inherited
        // you must chain them like this.
        super(str);
    }
}

Upvotes: 51

Chris Dennett
Chris Dennett

Reputation: 22741

Say if you have 

/**
 * 
 */
public KKSSocket(final KKSApp app, final String name) {
    this.app = app;
    this.name = name;
    ...
}

then a sub-class named KKSUDPSocket extending KKSSocket could have:

/**
 * @param app
 * @param path
 * @param remoteAddr
 */
public KKSUDPSocket(KKSApp app, String path, KKSAddress remoteAddr) {
    super(app, path, remoteAddr);
}

and

/**
 * @param app
 * @param path
 */
public KKSUDPSocket(KKSApp app, String path) {
    super(app, path);
}

You simply pass the arguments up the constructor chain, like method calls to super classes, but using super(...) which references the super-class constructor and passes in the given args.

Upvotes: 1

RichardOD
RichardOD

Reputation: 29157

Read about the super keyword (Scroll down the Subclass Constructors). If I understand your question, you probably want to call a superclass constructor?

It is worth noting that the Java compiler will automatically put in a no-arg constructor call to the superclass if you do not explicitly invoke a superclass constructor.

Upvotes: 4

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