CODEWITHSUNDEEP
pythontkinter
varsha_holla
varsha_holla

Reputation: 862

How to pop up a message while processing - python

I want to know, how to pop-up messages while processing/executing a program/function. I mean, 

def Select():
    path=tkFileDialog.askopenfilename(filetypes=[("Image File",'.jpg')])
    im = skimage.io.imread(path, as_grey=True)
    im = skimage.img_as_ubyte(im)
    im /= 32
    g = skimage.feature.greycomatrix(im, [1], [0], levels=8, symmetric=False, normed=True)
    cont = skimage.feature.greycoprops(g, 'contrast')[0][0]
    cont_list1.append(cont)
    ene = skimage.feature.greycoprops(g, 'energy')[0][0]
    ene_list1.append(ene)
    homo = skimage.feature.greycoprops(g, 'homogeneity')[0][0]
    homo_list1.append(homo)
    cor = skimage.feature.greycoprops(g, 'correlation')[0][0]
    cor_list1.append(cor)
    dis = skimage.feature.greycoprops(g, 'dissimilarity')[0][0]
    dis_list1.append(dis)

I want to display a message stating Features are being calculated, and once it calculates, the message should disappear.

But I don't need the ok button.I don't know how to achieve this.The result of these calculations will be displayed in separate Entry box. Any suggestions are welcome.

Upvotes: 3

Views: 6935

Answers (1)

User
User

Reputation: 14873

Have a look at this. It opens a window with the text and when the computation is done the text is changed to the result.

>>> import time
>>> def processingPleaseWait(text, function):
    import Tkinter, time, threading
    window = Tkinter.Toplevel() # or tkinter.Tk()
    # code before computation starts
    label = Tkinter.Label(window, text = text)
    label.pack()
    done = []
    def call():
        result = function()
        done.append(result)

    thread = threading.Thread(target = call)
    thread.start() # start parallel computation
    while thread.is_alive():
        # code while computing
        window.update()
        time.sleep(0.001)
    # code when computation is done
    label['text'] = str(done)


>>> processingPleaseWait('waiting 2 seconds...', lambda: time.sleep(2))

Upvotes: 4

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