CODEWITHSUNDEEP
haskell
Fof
Fof

Reputation: 395

Haskell parse error in function definition

I'm trying to compile this function:

fff [] _ = []
fff (x:xs) ys
   | r == [] = xs1
   | otherwise ys ++ xs1
   where r = filter (x<) ys 
         xs1 = fff xs ys

But I get this error:

Test.hs:14:4: parse error on input `where'

Failed, modules loaded: none.

Any help to solve it?

Thanks,
Sebastián.

Upvotes: 0

Views: 737

Answers (1)

Lee Duhem
Lee Duhem

Reputation: 15121

You missed the required = after otherwise.

By the way, r == [] better be replaced by the more general null r.

Try this:

fff [] _ = []
fff (x:xs) ys
    | r == [] = xs1
    | otherwise = ys ++ xs1
    where r = filter (x<) ys 
          xs1 = fff xs ys

Upvotes: 2

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