CODEWITHSUNDEEP
phpregex
user2129623
user2129623

Reputation: 2257

regex to match digit word in numbers

Here is my regex to validate the phone number. which works fine for various numbers like 1223534345 etc .

/(?:\((\+?\d+)?\)|(\+\d{0,3}))? ?\d{2,3}([-\.]?\d{2,3} ?){3,4}/

snippet:

foreach ($words as $word){

    $arrwords = array(0=>'zero',1=>'one',2=>'two',3=>'three',4=>'four',5=>'five',6=>'six',7=>'seven',8=>'eight',9=>'nine');
    preg_match_all('/[A-za-z]+/', $text, $matches);
    $arr=$matches[0];
    foreach($arr as $v)
    {
       $text= str_replace($v,array_search($v,$arrwords),$text);
    }

    $pattern = '/(?:\((\+?\d+)?\)|(\+\d{0,3}))? ?\d{2,3}([-\.]?\d{2,3} ?){3,4}/';
    preg_match_all($pattern, $text, $matches, PREG_OFFSET_CAPTURE );
    $this->pushToResultSet($matches);
}

But I want to add exploits like this:

1223five34345, it should also be considered as 1223534345 and should be filtered. Is this possible ?

Upvotes: 1

Views: 453

Answers (1)

Shankar Narayana Damodaran
Shankar Narayana Damodaran

Reputation: 68476

Explanation :

Map all those words as shown in the $arrwords , now do a preg_match_all() to check for all the occurrences of the words. Grab them in array. Now loop that array and check if that value exists in the $arrwords array , if found map the key to the string.

<?php
$arrwords = array(0=>'zero',1=>'one',2=>'two',3=>'three',4=>'four',5=>'five',6=>'six',7=>'seven',8=>'eight',9=>'nine');
$str='I won total five prize';
preg_match_all('/[A-za-z]+/', $str, $matches);
$arr=$matches[0];
foreach($arr as $v)
{
    $v = strtolower($v); //<--- Fail safe !!
    if(in_array($v,$arrwords))
    {
    $str = str_replace($v,array_search($v,$arrwords),$str);
    }
}
echo $str; //I won total 5 prize

You can now validate this $str with your regular expression.

Upvotes: 2

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