Reputation: 22696
I'm sure this is probably very simple but I can't figure out how to slice a pandas HDFStore table by its datetime index to get a specific range of rows.
I have a table that looks like this:
mdstore = pd.HDFStore(store.h5)
histTable = '/ES_USD20120615_MIDPOINT30s'
print(mdstore[histTable])
open high low close volume WAP \
date
2011-12-04 23:00:00 1266.000 1266.000 1266.000 1266.000 -1 -1
2011-12-04 23:00:30 1266.000 1272.375 1240.625 1240.875 -1 -1
2011-12-04 23:01:00 1240.875 1242.250 1240.500 1242.125 -1 -1
...
[488000 rows x 7 columns]
For example I'd like to get the range from 2012-01-11 23:00:00 to 2012-01-12 22:30:00. If it were in a df I would just use datetimes to slice on the index, but I can't figure out how to do that directly from the store table so I don't have to load the whole thing into memory.
I tried mdstore.select(histTable, where='index>20120111')
and that worked in as much as I got everything on the 11th and 12th, but I couldn't see how to add a time in.
Upvotes: 4
Views: 2463
Reputation: 128918
Example is here needs pandas >= 0.13.0
In [2]: df = DataFrame(np.random.randn(5),index=date_range('20130101 09:00:00',periods=5,freq='s'))
In [3]: df
Out[3]:
0
2013-01-01 09:00:00 -0.110577
2013-01-01 09:00:01 -0.420989
2013-01-01 09:00:02 0.656626
2013-01-01 09:00:03 -0.350615
2013-01-01 09:00:04 -0.830469
[5 rows x 1 columns]
In [4]: df.to_hdf('test.h5','data',mode='w',format='table')
Specify it as a quoted string
In [8]: pd.read_hdf('test.h5','data',where='index>"20130101 09:00:01" & index<"20130101 09:00:04"')
Out[8]:
0
2013-01-01 09:00:02 0.656626
2013-01-01 09:00:03 -0.350615
[2 rows x 1 columns]
You can also specify it directly as a Timestamp
In [10]: pd.read_hdf('test.h5','data',where='index>Timestamp("20130101 09:00:01") & index<Timestamp("20130101 09:00:04")')
Out[10]:
0
2013-01-01 09:00:02 0.656626
2013-01-01 09:00:03 -0.350615
[2 rows x 1 columns]
Upvotes: 8