CODEWITHSUNDEEP
javaparameter-passinganonymous-class
jmt
jmt

Reputation: 223

Passing parameter to anonymous class in Java

i'm trying to write anonymous inner class 

interface Face{
    void seeThis(String what);
}


class Eyes {
    public void show(Face f){}
}

public class Seen {

    public void test() {
        Eyes e = new Eyes();
        e.show(new Face() {

            @Override
            public void seeThis(String what){
                System.out.print(what);
            }
        });

    public static void main(String[] args) {
        Seen s = new Seen();
        s.test();
    }
}

How to call seeThis() and how to pass parameter to it?

Upvotes: 0

Views: 2796

Answers (1)

Alexey Malev
Alexey Malev

Reputation: 6533

Method seeThis() belongs to Face class, which instance is anonymous and thus cannot be reached without storing reference to it. If you want to store a reference, you can do this in the following way:

public class Seen {
    public Face face;

    ....

    this.face = new Face() { ... };
    e.show(this.face);

And then,

Seen s = new Seen();
s.face.seeThis();

Now, regarding passing the parameter. You have two options - declare parameter outside of anonymous class and make it final in order to be reachable by this anonymous class, or replace anonymous class with normal one and pass the parameter to its constructor:

Approach one:

final int parameter = 5;

...(new Face() {
        @Override
        public void seeThis() {
            System.out.println(parameter);
        }
    });

Approach two:

public class MyFace implements Face() {
    private final int parameter;

    public MyFace(int parameter) {
        this.parameter = parameter;
    }

    @Override
    public void seeThis() {
        System.out.println(parameter);
    }
}

Then,

...
e.show(new MyFace(10));

Upvotes: 2

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