CODEWITHSUNDEEP
phparrays
Leo T Abraham
Leo T Abraham

Reputation: 2437

Check one array is completely present in another

I have two arrays:

$array1 = Array ( [0] => stdClass Object ( [user_id] => 4 ) [1] => stdClass Object ( [user_id] => 5 ) ) 

$array2 = Array ( [0] => stdClass Object ( [usr_id] => 4 ) [1] => stdClass Object ( [usr_id] => 5 ) )

I want to check, all elements of $array2 is present in $array1 or not.

How can I do that?

I have searched, but couldn't find a suitable solution for my array.

Note: I want this comparison, without changing the array format.

Upvotes: 1

Views: 87

Answers (4)

Leo T Abraham
Leo T Abraham

Reputation: 2437

$checking = (count(array_intersect($arr2, $arr1)) == count($arr2))?1:0;

If all elements of $arr2 is present in $arr1 then it will return 1.

Upvotes: 0

Arne De Smedt
Arne De Smedt

Reputation: 755

try array_intersect()

$contains = count(array_intersect($array2, $array1)) == count($array2);

Upvotes: 0

Anand Solanki
Anand Solanki

Reputation: 3425

Try this:

$fullyExists = (count($array2) == count(array_intersect($array2, $array1));

Upvotes: 1

Gwenc37
Gwenc37

Reputation: 2048

I don't know it there is a PHP function for that, but you can do your own:

function arrayIsIncluded($array1,$array2){
    foreach($array2 as $key => $value){
        if (!in_array($value,$array1)){
            return false;
        }
    }
    return true;
}

Upvotes: 1

Related Questions