Reputation: 39
In my c# application which developed with c# in visual studio 2012 I created a file by this command :
System.IO.File.Create("config.conf");
after that in the next line I want to use the file by this command :
System.IO.StreamReader rd = new System.IO.StreamReader("config.conf");
But I get This exception :
"The process cannot access the file '\config.far' because it is being used by >another process."
I used thread.sleep(2000) to make application wait but still it doesn't answer.
I will appropriate any help.
Upvotes: 0
Views: 292
Reputation: 3185
When working with files, it is always a good idea to dispose of the file once you are done.
This can be done by two different techniques, the most popular one is using a "using" statement:
using (FileStream fileStream = File.Create(fileNamePath))
{
// insert logic here, for example:
fileStream.SetLength(fileSize);
}
The other one, is calling the .Dispose method.
Upvotes: 0
Reputation: 300
using(var conf = System.IO.File.Create("config.conf"))
{
using (var rd = new System.IO.StreamReader(conf))
{
// Do whatever you want to do with the file here
}
}
Upvotes: 1
Reputation: 56727
The problem is that File.Create
returns a stream to the file. That is: The file is already opened for you!
You could do this:
using (System.IO.StreamReader rd = new System.IO.StreamReader(System.IO.File.Create("config.conf")))
{
...
}
By the way, this does not really make sense. What do you expect an empty, newly created file to contain?
Upvotes: 0
Reputation: 391634
File.Create creates the file and returns a FileStream
holding the file open.
You can do this:
System.IO.File.Create("config.conf").Dispose();
by disposing of the returned stream object, you close the file.
Or you can do this:
using (var stream = File.Create("config.conf"))
using (var rd = new StreamReader(stream))
{
.... rest of your code here
Additionally, since disposing of the StreamReader
will also dispose of the underlying stream, you can reduce this to just:
using (var rd = new StreamReader(File.Create("config.conf")))
{
.... rest of your code here
Final question: Why are you opening a newly created stream for reading? It will contain nothing, so there's nothing to read.
Upvotes: 5