Reputation: 811
I need to use as PathParam the path of a file, how can I do? Should I use URLEncode e URLDecode? Can someone give me an example?
The structure of my ws is:
@Path("/{filePath}")
public Response convert(@PathParam("filePath") String filePath) throws Throwable
{
..
}
Thanks in advance
Upvotes: 0
Views: 844
Reputation: 10961
Use the .*
regex for the pathParam. Otherwise jax-rs will only expect one segment. Then resolve the path against your base-directory.
@GET
@Path("/backup/{filePath : .*}")
public Response convert(@PathParam("filePath") String filePath) {
java.nio.file.Path absolutePath = Paths.get("/path/to/backup", filePath);
return Response.ok(absolutePath.toString()).build();
}
Paths.get("C:/path/to/backup", filePath)
should work if you are using windows. (Untested)
Unrelated: I don’t see a reason for throwing a Throwable
.
Upvotes: 0