CODEWITHSUNDEEP
javaclassconstructorsuperclass
sirnomnomz
sirnomnomz

Reputation: 653

implicit super constructor Person() is undefined. Must explicitly invoke another constructor?

I am working on a project and i am getting the error "implicit super constructor Person() is undefined. Must explicitly invoke another constructor" and i don't quite understand it.

Here is my person class:

public class Person {
    public Person(String name, double DOB){

    }
}

And my student class when trying to implement the person class, and giving it an instructor variable.

public class Student extends Person {

    public Student(String Instructor) {

    }

}

Upvotes: 46

Views: 161192

Answers (6)

Kim Thạch Nguyễn
Kim Thạch Nguyễn

Reputation: 87

An easy way to solve this problem that you can instantiate a no-argument constructor at super class.

Upvotes: 0

pxm
pxm

Reputation: 1611

If a constructor does not explicitly invoke a superclass constructor, the Java compiler automatically inserts a call to the no-argument constructor of the superclass.

If the super class does not have a

no-argument constructor, you will get a compile-time error. Object does have such a constructor, so if Object is the only superclass, there is no problem.

Reference: http://docs.oracle.com/javase/tutorial/java/IandI/super.html : (See under section 'SubClass Constructors')

So whenever dealing with parameterized constructors make a super(parameter1, parameter2 ..) call to the parent constructor. Also this super() call should be the FIRST line in your constructor block.

Or else, if a scenario demands, create an additional non-parameterized () constructor in the parent class

Upvotes: 67

Jaime Montoya
Jaime Montoya

Reputation: 7701

This is how I achieved it (in my case the superclass was Team and the subclass was Scorer):

// Team.java
public class Team {
    String team;
    int won;
    int drawn;
    int lost;
    int goalsFor;
    int goalsAgainst;
    Team(String team, int won, int drawn, int lost, int goalsFor, int goalsAgainst){
        this.team = team;
        this.won = won;
        this.drawn = drawn;
        this.lost = lost;
        this.goalsFor = goalsFor;
        this.goalsAgainst = goalsAgainst;
    }
    int matchesPlayed(){
        return won + drawn + lost;
    }
    int goalDifference(){
        return goalsFor - goalsAgainst;
    }
    int points(){
        return (won * 3) + (drawn * 1);
    }
}
// Scorer.java
public class Scorer extends Team{
    String player;
    int goalsScored;
    Scorer(String player, int goalsScored, String team, int won, int drawn, int lost, int goalsFor, int goalsAgainst){
        super(team, won, drawn, lost, goalsFor, goalsAgainst);
        this.player = player;
        this.goalsScored = goalsScored;
    }
    float contribution(){
        return (float)this.goalsScored / (float)this.goalsFor;
    }
    float goalsPerMatch(){
        return (float)this.goalsScored/(float)(this.won + this.drawn + this.lost);
    }
}

Upvotes: 8

EasterBunnyBugSmasher
EasterBunnyBugSmasher

Reputation: 1582

you can't create an instance without calling a constructor of its super class. And the jvm doesn't know how to call Person(String, double) from your Student(String) constructor.

Upvotes: 0

Rogue
Rogue

Reputation: 11483

You need to make a super call to your defined constructor:

public Student(String instructor) {
    super(/* name */, /* date of birth */);
}

You can't just call super() because that constructor is not defined.

Upvotes: 13

rgettman
rgettman

Reputation: 178263

When creating a subclass constructor, if you don't explicitly call a superclass constructor with super, then Java will insert an implicit call to the no-arg "default" superclass constructor, i.e. super();.

However, your superclass Person doesn't have a no-arg constructor. Either supply an explicit no-arg constructor in Person or explicitly call the existing superclass constructor in the Student constructor.

Upvotes: 2

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