CODEWITHSUNDEEP
cassemblyshellcode
user2199104
user2199104

Reputation: 115

asm shellcode in C buffer - prologue

I try to build a function in a buffer in C. with gdb i can translate

push   rbp
mov    rbp,rsp
(...)
leave
ret

to 

0x55
0x48 0x89 0xe5
(...)
0xc9
0xc3

So I wrote a C code:

int main()
{
   char buffer[]={0x55,0x48,0x89,0xe5,0xc9,0xc3};
   void (*j)(void)=buffer;
   j();
}

but my program seems to crash at the intruction "push rbp" (0x55 in the buffer) Do you know why?

Upvotes: 1

Views: 282

Answers (1)

Jester
Jester

Reputation: 58762

The usual cause is that the stack (where your buffer is stored) is not executable. There are primarily two ways around that:

  1. compile/link such that the stack is marked executable (ie. gcc -z execstack)
  2. use mprotect at runtime to mark the page where your code is executable

Upvotes: 3

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