CODEWITHSUNDEEP
phpregexsplit
MikO
MikO

Reputation: 18751

Split string on a space before one of two whitelisted words

I have strings like this:

wh4tever_(h4r4ct3rs +syMb0|s! ASC
wh4tever_(h4r4ct3rs +syMb0|s! DESC

I don't know what the first characters are, but I know that they end by ' ASC' or ' DESC', and I want to split them so that I get an array like:

array(
    [0] => 'wh4tever_(h4r4ct3rs +syMb0|s!'
    [1] => 'ASC' //or 'DESC'
)

I know it must be absolutely easy using preg_split(), but regexps are something I assumed I'll never get on well with...

Upvotes: 0

Views: 80

Answers (3)

anant prajapati
anant prajapati

Reputation: 177

Try This,

$str = "wh4tever_(h4r4ct3rs +syMb0|s! ASC";
$str1 = "wh4tever_(h4r4ct3rs +syMb0|s! ASC";


$ar = preg_split('/(ASC|DESC)/i', $str, -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);
$ar1 = preg_split('/(ASC|DESC)/i', $str1, -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);

print_r($ar);
print_r($ar1);

output : Array ( [0] => wh4tever_(h4r4ct3rs +syMb0|s! [1] => ASC ) Array ( [0] => wh4tever_(h4r4ct3rs +syMb0|s! [1] => DESC )

Upvotes: 3

Amal
Amal

Reputation: 76646

You can use the following regular expression with preg_split():

\s(?=(ASC|DESC))

Explanation:

  • \s - match any whitespace character
  • (?= - start of positive lookahead
    • (ASC|DESC) - ASC or DESC
  • ) - end of positive lookahead

Visualization:

enter image description here

Complete:

$str = 'wh4tever_(h4r4ct3rs +syMb0|s! ASC';
$arr = preg_split('/\s(?=(ASC|DESC))/', $str);
print_r($arr);

Output:

Array
(
    [0] => wh4tever_(h4r4ct3rs +syMb0|s!
    [1] => ASC
)

Demo

Upvotes: 3

Amit Joki
Amit Joki

Reputation: 59292

You can use this regex:

\s(?=(A|DE)SC)

and split it.

As sshashank124, pointed, it is an extremely good tool which is language agnostic.

Upvotes: 2

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