Reputation: 159
I'm trying to understand this code:
<?php
$list = array(-10=>1, 2, 3, "first_name"=>"mike", 4, 5, 10=>-2.3);
print_r(array_keys($list));
?>
Output:
Array (
[0] => -10
[1] => 0
[2] => 1
[3] => first_name
[4] => 2
[5] => 3
[6] => 10
)
I'm wondering why [4] => 2
and why [5] => 3
. I thought it would be [4] => 4
and [5] => 5
because they are both at index 4 and 5. I'm slightly confused as to what exactly is going on in this array, if possible could someone point me in the right direction.
Upvotes: 4
Views: 109
Reputation: 1136
It seems like when the key is not set, array_keys keeps the track of the last key assigned and will assign the consecutive number:
array(7) {
[0]=>
int(-10)
[1]=>
int(0) // first without key (starting on 0)
[2]=>
int(1) // second without key
[3]=>
string(10) "first_name"
[4]=>
int(2) // third without key
[5]=>
int(3) // fourth without key
[6]=>
int(10)
}
Upvotes: 0
Reputation: 9587
In your array, you are mixing key => value
with just value
.
-10 is your first key. Then because you are not defining a key for following items, it's automatically assigned in order.
Upvotes: 0
Reputation: 488
It's normal because PHP is waiting for a key.
$list = array(-10=>1, 2, 3, "first_name"=>"mike", 4, 5, 10=>-2.3);
And you don't give him in 2,3,4,5 so it gives a key automatic .
So ==> [0] => 2 , [1] => 3 , [2] => 4 and [3] => 5.
Upvotes: 1
Reputation: 1714
try this:
$list = array(-10=>1, 2 => null, 3=> null, "first_name"=>"mike", 4=> null, 5=> null, 10=>-2.3);
to have the result you want so 2, 3, 4 and 5 will be count as key instead of value
Upvotes: 1
Reputation: 360572
You're mixing keyed with keyless array entries, so it gets a bit wonky:
$list = array(
-10 => 1 // key is -10
=> 2 // no key given, use first available key: 0
=> 3 // no key given, use next available key: 1
"first_name" => "mike" // key provided, "first_name"
=> 4 // no key given, use next available: 2
=> 5 // again no key, next available: 3
10 => -2.3 // key provided: use 10
If you don't provide a key, PHP will assign one, starting at 0. If the potential new key would conflict with one already assigned, that potential key will be skipped until PHP finds one that CAN be used.
Upvotes: 6