CODEWITHSUNDEEP
javamemory-managementarraysjavacard
Abdou Abderrahmane
Abdou Abderrahmane

Reputation: 23

Byte array memory allocation on java card

I'm working on a project to manage strong authentication using a Java card, there is a server app that creates user IDs and PIN codes, it then loads the pin code on the smart card and it's signature, and here is the problem, when i try to load the signature on the card( which is a 64 bytes RSA SHA1 signature) i get the following exception thrown on card : 

checkFieldStore -> Security exception
throw_error(SECURITY_EXCEPTION)

i guess this has something to do with the way i'm handling the byte array memory allocation, here is my code : 

RSAPrivateKey  rsa_PrivateKey;
RSAPublicKey rsa_PublicKey;
KeyPair rsa_KeyPair;
Cipher cipherRSA;
Signature sig;
short expo;
short PIN;
byte[] pinSig = new byte[64];


public short verify (byte[] pin){

    sig = Signature.getInstance(Signature.ALG_RSA_SHA_PKCS1, false);
    sig.init(rsa_PublicKey, Signature.MODE_VERIFY);
    if( sig.verify(pin, (short)0, (short)pin.length, pinSig, (short)0, (short)pinSig.length)){
        return 1;
    }else{
        return 0;
    }
}

public void setpinSig( byte[] sig){


    pinSig = sig;
}

public void setPIN(short pin){

    PIN = pin;

}



public short isPIN(short pin){

    if ( pin != PIN )return 0;

    return 1;

}

The exception is thrown when i call the setpinSig method.

BTW: i tried setting a pin without a signature and checking it's validity successfuly

Upvotes: 0

Views: 1019

Answers (1)

Robert
Robert

Reputation: 42575

In case the pinSig value is always 64 bytes long you should use the following implementation:

public void setpinSig( byte[] sig){
    javacard.framework.Util.arrayCopy(sig, (short) 0, 
        pinSig, (short) 0, (short) 64);
}

Upvotes: 1

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