CODEWITHSUNDEEP
linuxbashshellgrep
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Reputation: 333

Grep filter not stop at first match

I am trying to use 

grep -o "javascript:add2BasketProd.*?jpg"

to extract string from 

javascript:add2BasketProd('xKonfGFJsakj', 'Tattoo-Bubble-Gum-7cm-Bubble-Gum.jpg')Funny-Glasses-and-Teeth-Toy-Candy-TC-747-.jpg

but it would give no output. So I changed the code to the following but the output I get is entire string and not until the first match of jpg. 

grep -o "javascript:add2BasketProd.*\?jpg"

My expected output is: 

javascript:add2BasketProd('xKonfGFJsakj', 'Tattoo-Bubble-Gum-7cm-Bubble-Gum.jpg

Can anyone suggest a solution?

Upvotes: 0

Views: 355

Answers (2)

anubhava
anubhava

Reputation: 784898

You can use egrep for advanced regex capabilities:

s='javascript:add2BasketProd('xKonfGFJsakj', 'Tattoo-Bubble-Gum-7cm-Bubble-Gum.jpg')Funny-Glasses-and-Teeth-Toy-Candy-TC-747-.jpg'
egrep -o "javascript:add2BasketProd.*?jpg" <<< "$s"
javascript:add2BasketProd(xKonfGFJsakj, Tattoo-Bubble-Gum-7cm-Bubble-Gum.jpg

Upvotes: 2

John1024
John1024

Reputation: 113814

grep uses POSIX style regular expression which are always greedy. If your grep supports the -P flag, you can use it to enable perl style regex which do support non-greedy matches:

grep -oP "javascript:add2BasketProd.*?jpg"

The GNU grep, which is used on linux, supports -P. The Mac OSX grep does not.

Upvotes: 2

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