CODEWITHSUNDEEP
iosnsstringnsurl
Justin Clarke
Justin Clarke

Reputation: 139

Convert UITextField values to strings

The point is for someone to enter their ClientID and API into two UITextField's and I'll pass them to a URL. Well I need to convert those to string. I have, but the app is crashing on running. What would be the best way to do this?

My code is below:

@interface LogInViewController : UIViewController

    @property (strong, nonatomic) IBOutlet UITextField *clientID;
    @property (strong, nonatomic) IBOutlet UITextField *clientAPI;

@end

@implementation LogInViewController {
    NSString *clientIDToString;
    NSString *clientAPIToString;
}

- (IBAction)signIn:(id)sender {
    clientIDToString = _clientID.text;
    clientAPIToString = _clientAPI.text;

    NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.digitalocean.com/droplets/?client_id=%p&api_key=%p", clientIDToString, clientAPIToString]];

}

Upvotes: 0

Views: 93

Answers (2)

Matteo Gobbi
Matteo Gobbi

Reputation: 17697

First of all don't use %p but use %@ in your string and so:

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.digitalocean.com/droplets/?client_id=%@&api_key=%@", clientIDToString, clientAPIToString]];

this is the reason of the crash.

Second thing: your @property should be weak and not strong because you are using IBOutlet.

Upvotes: 2

Logan
Logan

Reputation: 53112

This:

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.digitalocean.com/droplets/?client_id=%p&api_key=%p", clientIDToString, clientAPIToString]];

Should be:

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://api.digitalocean.com/droplets/?client_id=%@&api_key=%@", clientIDToString, clientAPIToString]];

Upvotes: 1

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