Reputation: 29431
I've miss-write my variables names using i
for two variables, one is an int
and the other Uint16
like so :
for(int i = 0; i <= 5; i++) {
for(Uint16 ch = 5; ch < 20; ++ch) {
Uint16 i = ch;
//Some code
cout << i;
}
}
Using clang x86 5.1 it does compile, but which i
will be displayed ? Is their a special rule ?
Upvotes: 0
Views: 98
Reputation: 13661
In an inner scope, a variable declaration will shadow any previous declaration. In your code sample the output will be the value of ch
on each loop iteration.
If you were to output the value of i
outside the inner for, the output would be the value of the i
declared in the first for loop.
Upvotes: 1