CODEWITHSUNDEEP
javascriptjquery
Tejas
Tejas

Reputation: 585

jQuery inArray() returns -1 if array contains single element

jQuery inArray returns -1 if the array contains single element.

var a = Array(1);
console.log($.inArray(1,a));

This returns -1. But if the array contains 2 or more elements it works perfectly.

var a = Array(1,2,3);
console.log($.inArray(1,a));

Returns perfect position.

Upvotes: 4

Views: 159

Answers (1)

Denys Séguret
Denys Séguret

Reputation: 382092

Contrary to what you seem to think, Array(1) doesn't create an array with element 1 but an array of size 1. That's a specific behavior you get when you pass only one argument and it's an integer.

From the MDN :

If the only argument passed to the Array constructor is an integer between 0 and 2^32-1 (inclusive), this returns a new JavaScript array with length set to that number.

You should probably almost never use this Array constructor whose strange behavior leads to many bugs and which is mostly useless. Use this :

var a = [1];

Upvotes: 6

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