CODEWITHSUNDEEP
phpdatecompare
user2649343
user2649343

Reputation: 147

Date not today or before and not more than year from today check php

i need to check and give error if any of these criterion are true: the date selected by user is:

I am checking in this code

if((strtotime($_POST["sch_date"])<=strtotime(date("d/m/Y"))) OR (((strtotime(date("d/m/Y",strtotime("+1 year"))))-(strtotime($_POST["sch_date"])))/(60*60*24)<0))

but this give haphazard results meaning it shows error if the selected date is 2 days less than 1 year. Can someone please advice how to go about this?

Upvotes: 2

Views: 171

Answers (2)

Mark Miller
Mark Miller

Reputation: 7447

Your attempt was pretty close, maybe just a little over-complicated, try this:

date_default_timezone_set('America/Los_Angeles'); // Set your timezone

// Assuming $_POST['sch_date'] is in the form 'd/m/Y'
$date = str_replace('/', '-', $_POST['sch_date']);

if (strtotime($date) <= strtotime('today') || strtotime($date) > strtotime('+ 1 year'))
    echo "error";

Note: This assumes $date is a date in some standard format - m/d/Y or d-m-Y or Y-m-d etc., but not a datetime. See here for standard formats It will give an error if $date is today or any date before today, or if $date is after 1 year from today.

To convert your non-standard d/m/y, you need this, which has been added to the code above:

$date = str_replace('/', '-', $_POST['sch_date']);

Upvotes: 0

John Conde
John Conde

Reputation: 219844

Using DateTime() makes this easy as they are comparable:

$dateSelected   = DateTime::createFromFormat('d/m/Y', '18/04/2014'); // put your date here
$today          = new DateTime();
$oneYearFromNow = new DateTime('+1 year');
if ($dateSelected <= $today && $dateSelected > $oneYearFromNow) {
    // we're good
}
else {
    // it's the end of the world!
}

Upvotes: 4

Related Questions