Reputation: 59
I have table with id (PK,AI), name and date, when users register I set date = CURDATE().
I have a PHP page where I have to list the names where CURDATE() >= (date + 3 days) excluding weekends (Sat and Sunday) means I list names of users who completed the registration before 3 days but I don't count weekends.
which means if someone register on Monday, he should listed on the page on Thursday and if he registered on Friday, the page list him only on Wednesday (excluded weekends)
Is there any method in MySQL to accomplish this ?
Upvotes: 0
Views: 594
Reputation: 2235
Easy in MySQL.
SELECT CURRENT_DATE + interval (3 + 2*(weekday(CURRENt_DATE) > 1)) day;
Thanks to @JamesBlond for the table, saves me to explain. ;-)
EDIT: I was confused by the (index-killing) way to request data: normally you should try taking the date from the table unmodified and to fiddle with your CURRENT_DATE data.
As long as I understand you right, it should be the following, so you also could simply use a CASE WHEN
clasue, that is more readable and easier to adopt.
thedate - interval ( 3 + 2*(weekday(thedate) < 3) + (weekday(thedate) > 4) * (weekday(thedate)-4)) DAY AS 3_days_before
http://www.sqlfiddle.com/#!2/49731/9/0
THEDATE WEEKDAY(THEDATE) THEDATE_FORMATTED 3_DAYS_BEFORE FORMATTED_3_DAYS_BEFORE
April, 27 2014 00:00:00+0000 6 Sunday April, 22 2014 00:00:00+0000 Tuesday
April, 28 2014 00:00:00+0000 0 Monday April, 23 2014 00:00:00+0000 Wednesday
April, 29 2014 00:00:00+0000 1 Tuesday April, 24 2014 00:00:00+0000 Thursday
April, 30 2014 00:00:00+0000 2 Wednesday April, 25 2014 00:00:00+0000 Friday
May, 01 2014 00:00:00+0000 3 Thursday April, 28 2014 00:00:00+0000 Monday
May, 02 2014 00:00:00+0000 4 Friday April, 29 2014 00:00:00+0000 Tuesday
May, 03 2014 00:00:00+0000 5 Saturday April, 29 2014 00:00:00+0000 Tuesday
May, 04 2014 00:00:00+0000 6 Sunday April, 29 2014 00:00:00+0000 Tuesday
May, 05 2014 00:00:00+0000 0 Monday April, 30 2014 00:00:00+0000 Wednesday
May, 06 2014 00:00:00+0000 1 Tuesday May, 01 2014 00:00:00+0000 Thursday
May, 07 2014 00:00:00+0000 2 Wednesday May, 02 2014 00:00:00+0000 Friday
Upvotes: 0
Reputation: 2934
Instead of doing a complex mysql query, could you not just pass in a different date to check against, depending on the weekday from your php script?
So, instead of comparing in your sql query your date+3days <= today, pass in a variable for the date offset or just calculate the date in php and pass the date in.
day of the week | offset
1 | 5
2 | 5
3 | 5
4 | 3
5 | 3
6 | 4
7 | 5
Upvotes: 0