CODEWITHSUNDEEP
iosxmppopenfirexmppframework
Oleg
Oleg

Reputation: 432

XMPP Get number of room members without connecting to a room

I have: ios app; Server: openfire; Framework: xmppframework from Robby Hanson.

The logic of the app is when user has logged in, the app will push him into a random room which has the fewest number of members.

The app successfully gets a list of all rooms on start from the server. But I need to know which of these rooms have an empty place for a user!

There is a method called "fetchmemberslist", but it only returns you a list of members of a room when you are connected to that room.

I need something that will do the same without connecting to a room.

Think if I have 1000 rooms. Using this method the app needs to connect to every room, set delegate, activate, wait for IQ, remove delegate, deactivate and at the and go thru an array to find one with the fewest members. Isn't it too much to do?

I have dig over the whole internet and everything leads to getting a member list when you are connected to a room.

Is there a way of doing this without connecting a room.

Many thanks in advance!

Upvotes: 3

Views: 1866

Answers (1)

vitalyster
vitalyster

Reputation: 5266

1) fetchMemberList: queries room members, not list of people who are present in room now. Are you really want members, not online users count? Anyway, if you are room admin, this query works without joining room.

2) If you want to query online users, you should use different query - see http://xmpp.org/extensions/xep-0045.html#disco-roomitems

3) Also, no one can forbid you to implement room members/onlines count on the server side and create custom query like <iq id='123' type='get'><freeroom xmlns='my:freeroom:query' /></iq> with response of room JID like <iq id='123' type='result'><freeroom xmlns='my:freeroom:query'><jid>[email protected]</jid></freeroom></iq> where roomname was found by server itself.

Upvotes: 2

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