Reputation: 1394
I have the following URL:
http://127.0.0.1:8000/databaseadd/q=DQ-TDOXRTA?recipe=&recipe=&recipe=&recipe=&recipe=
I'd like to match if the keyword "recipe=" is found in the url.
I have the following line in django url.py but it's not working:
url(r'recipe=', 'plots.views.add_recipe'),
Are the "&" and the "?" throwing it off?
Thanks!
Alex
Upvotes: 0
Views: 164
Reputation: 10787
Part after the ?
not used in the url dispatching process because it contains GET parameters. Otherwise you will not be able to use a GET request with parameters on patterns like r'^foo/&'
(ampersand at the end means the end of the string, and without it it would be harder to use patterns like r'^foo/'
and r'^foo/bar/'
at the same time).
So for your url the pattern should look like r'^databaseadd/q=DQ-TDOXRTA&'
and then in add_recipe
view you need to check for the recipe
GET parameter.
Upvotes: 2
Reputation: 3838
I'd like to match if the keyword "recipe=" is found in the url
You could try something like :
import re;
re.match (r'.*recipe=.*', "http://127.0.0.1:8000/databaseadd/q=DQ-TDOXRTA?recipe=&recipe=&recipe=&recipe=&recipe=")
Upvotes: 0