CODEWITHSUNDEEP
c++
Fox-3
Fox-3

Reputation: 483

C++ command line input from a text file

I would like to take numbers from a .txt file and input them through the command line into a program like the example below. I run the exe using ./program < input.txt. However it prints random numbers. What am I doing wrong?

#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
//print 1st number
cout << argv[1];
}

Upvotes: 4

Views: 9169

Answers (3)

R Sahu
R Sahu

Reputation: 206567

cout << argv[1];

is equivalent to:

char* arg = argv[1];
cout << arg;

It just prints the value of the first argument to the program

In your case, you didn't provide an argument to the program.

When you use,

./program < input.txt

the contents of input.ext becomes stdin of your program. You can process that using:

int c;
while ( (c = fgetc(stdin)) != EOF )
{
   fputc(c, stdout);
}

If you want to stay with C++ streams, you can use:

int c;
while ( (c = cin.get()) != EOF )
{
   cout.put(c);
}

Upvotes: 3

RichS
RichS

Reputation: 943

You can do this:

./program $(cat input.txt)

This does the trick.

For example, if input.txt has numbers separated by spaces:

33 1212 1555

Running: 

./program $(cat input.txt)

prints 33 to the terminal.

Upvotes: 2

user2672165
user2672165

Reputation: 3049

To be able to use argv numbers need to be supplied as arguments, i.e.

./program 23 45 67

For ./program < input.txt you need to read from cin (standard input).

#include <iostream>
using namespace std;
int n;
int main()
{
   cin >> n;
   cout << n;
}

Upvotes: 1

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